(-16x+16)/(x^2-1)

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Solution for (-16x+16)/(x^2-1) equation: 


D( x )

x^2-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

(16-16*x)/(x^2-1) = 0

16-16*x = 0 // - 16

-16*x = -16 // : -16

x = -16/(-16)

x = 1

x in { 1} 

x belongs to the empty set

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